ICSE Class 10 Maths Competency Focused Practice Questions Solution-Long Answer Questions-1 (Graph based)

Maths Competency Focused Practice Questions Solution

Long Answer Questions-1 (Graph based)- 5 marks

Question 106
Plot the points A(2, 2) and B(6, -2) in the graph and answer the following :

(a) Reflect points A in origin to point D and write the co-ordinates of point D.

(b) Reflect points A in line y = -2 to point C and write the co-ordinates of point C.

(c) Find a point P on CD which is invariant under reflection in x = 0, write its co-ordinates.

(d) Write the geometrical name of the closed figure ABCD.

(e) Write the co-ordinates of the point of intersection of the diagonals of ABCD.

Answer:

The graph is shown below:

maths-competency-focused=practice-questions-solution

From graph,

(a) Co-ordinates of D = (-2, -2).

(b) Co-ordinates of C = (2, -6).

(c) Point P(0, -4) lies on y-axis.

∴ It is invariant under reflection in x = 0.

Co-ordinates of P = (0, -4).

(d) ABCD is a square.

(e) H is the point of intersection of diagonals of ABCD.

Co-ordinates of H = (2, -2).


Question 107
Plot points A(0, 3), B(4, 0), C(6, 2) and D(5, 0). Reflect the points as given below and write their coordinates:

(a) Reflect A on x-axis to A’.

(b) Reflect B on y-axis to B’.

(c) Reflect C on x-axis to C’.

(d) D remain invariant when reflected on the line whose equation is …………… .

(e) Join the points A, B, C, D, C’, B, A’, B’ and A to form a closed figure. Name the closed figure BCDC’.

Answer:

The graph is shown below:

maths-competency-focused=practice-questions-solution


(a) Coordinates of A’ = (0, -3).

(b) Coordinates of B’ = (-4, 0).

(c) Coordinates of C’ = (6, -2).

(d) D lies on x-axis.

∴ It is invariant in the line x-axis or y = 0.

D remain invariant when reflected on the line whose equation is y = 0.

(e) BCDC’ is a concave quadrilateral.


Question 108
The following data represents the daily wages in rupees of a certain number of employees of a company:

Daily wages (in ₹)No. of Employees
30 – 408
40 – 5014
50 – 6012
60 – 7017
70 – 8020
80 – 9026
90 – 10013
100 – 11010

Use a graph to answer the following questions:

(a) Represent the above distribution by an ogive.

(b) Find the following on the graph drawn:

(i) median wage.

(ii) percentage of employees who earn more than ₹ 84 per day.

(iii) number of employees who earn ₹56 and below.

Answer:

(a) Cumulative frequency distribution table:

Daily wages (in ₹)No. of Employees (f)Cumulative frequency (cum f)
30 – 4088
40 – 501422
50 – 601234
60 – 701751
70 – 802071
80 – 902697
90 – 10013110
100 – 11010120

Here, n = 120 (even)

Median = n/2 = 120/2 = 60 th term

maths-competency-focused=practice-questions-solution

Steps of construction :

Plotting the points (40, 8), (50, 22), (60, 34), (70, 51), (80, 71), (90, 97), (100, 110) and (110, 120) and making a cumulative frequency graph, we get:

(b) (i) Median wage = 60 th term = ₹74.

(ii) No. of employees earning more than ₹ 84 per day = 120 – 81 = 39.

Percentage of employees earning more than ₹84

\[=\frac{No.\;of\;employees\;earning\;more\;than\;₹84\;}{Total\;employees}\times100\%\\=\frac{39}{120}\times100\;\%\\=\frac{65}2=32.5\%\]

Hence, Percentage of employees earning more than ₹84 = 32.5%

(iii) From graph,

I = 30.

Hence, No. of employees earning less than or equal to ₹ 56 per day = 30.


Question 109
Study the graph and answer the questions that follow:


(a) Make a frequency table for the information provided in the graph.

(b) The number of students whose height is less than 150 cm.

(c) The total number of students.

(d) The modal height.

(e) The difference in the modal height and the mean height, if the average height of the students is 145.5 cm.

Answer:

(a) Frequency table:

ClassFrequency (f) Cumulative frequency (cu .f.)
120 – 13066
130 – 1402935
140 – 1503469
150 – 1602291
160 – 17012103

From the table,

(b) The number of students whose height is less than 150 cm = 69.

(c) The total number of students = 103.

From graph,

(d) The modal height = 143 cm.

(e) Mean height = Average height = 145.5

Difference in the modal height and the mean height :

145.5 – 143 = 2.5 cm

Hence, difference between modal height and the mean height = 2.5 cm


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